![Solution | What's the result when we reflect y=\sin x twice? | Trigonometry: Triangles to Functions | Underground Mathematics Solution | What's the result when we reflect y=\sin x twice? | Trigonometry: Triangles to Functions | Underground Mathematics](https://undergroundmathematics.org/trigonometry-triangles-to-functions/r7577/images/sin2.png)
Solution | What's the result when we reflect y=\sin x twice? | Trigonometry: Triangles to Functions | Underground Mathematics
![From the curve y = sin x, graph the functiony = sin(π2+x) which is cos x - Mathematics | Shaalaa.com From the curve y = sin x, graph the functiony = sin(π2+x) which is cos x - Mathematics | Shaalaa.com](https://www.shaalaa.com/images/_4:da98b1e75b3840fe9830d854ccf6b8a8.png)
From the curve y = sin x, graph the functiony = sin(π2+x) which is cos x - Mathematics | Shaalaa.com
![Sketch the Graph of the Following Pair of Functions on the Same Axes: F ( X ) = Sin X , G ( X ) = Sin ( X + π 4 ) - Mathematics | Shaalaa.com Sketch the Graph of the Following Pair of Functions on the Same Axes: F ( X ) = Sin X , G ( X ) = Sin ( X + π 4 ) - Mathematics | Shaalaa.com](https://www.shaalaa.com/images/_4:8f3facea18aa42b794380e7f065ac982.png)
Sketch the Graph of the Following Pair of Functions on the Same Axes: F ( X ) = Sin X , G ( X ) = Sin ( X + π 4 ) - Mathematics | Shaalaa.com
![Find the range of the function algebraically: y = sin(x - pi/6) + sin(x + pi/6). | Homework.Study.com Find the range of the function algebraically: y = sin(x - pi/6) + sin(x + pi/6). | Homework.Study.com](https://homework.study.com/cimages/multimages/16/sdy4148658511110477985972.png)
Find the range of the function algebraically: y = sin(x - pi/6) + sin(x + pi/6). | Homework.Study.com
![The area of the region bounded by the curve y = "sin" x between the ordinates x=0, x=pi/2 and the X-"axis" is The area of the region bounded by the curve y = "sin" x between the ordinates x=0, x=pi/2 and the X-"axis" is](https://d10lpgp6xz60nq.cloudfront.net/physics_images/ARH_NCERT_EXE_MATH_XII_C08_S01_030_S01.png)
The area of the region bounded by the curve y = "sin" x between the ordinates x=0, x=pi/2 and the X-"axis" is
![trigonometry - Graph the following function: $y = \sin \frac{1}{2}\left(x -\frac{\pi}{6}\right)$ - Mathematics Stack Exchange trigonometry - Graph the following function: $y = \sin \frac{1}{2}\left(x -\frac{\pi}{6}\right)$ - Mathematics Stack Exchange](https://i.stack.imgur.com/2iAhu.jpg)